READ THIS BECAUSE...
PROPER POWER FACTOR CORRECTION CAPACITOR SELECTION IS CRITICAL. |
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APPLYING CAPACITOR UNITS |
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KVAR UNITS - INDIVIDUAL MOTORS |
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Power Factor Correction Capacitors can be applied |
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There are four different methods of selecting the |
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at individual motors, distribution panels, or on the |
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proper size KVAR units for induction motors. |
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main service panel. Fixed Capacitors can be connected |
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Choose from one of these methods below based on |
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at all three locations, or Automatic Capacitor |
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what information you have available. |
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Systems can be installed on the main service panel. |
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Fixed Capacitors are permanent values of KVAR connected to the
electrical system, while Automatic |
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1) |
Use actual load measurements of KW and Power |
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Factor. This information can be used with Table |
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Capacitor Systems vary the amount of KVAR that is |
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3 below to calculate the KVAR necessary for a desired |
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connected based on sensing the entire electrical |
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Power Factor. |
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system requirements. If plant loads vary widely |
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during any 24 hour period, large fixed capacitors at |
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2) |
Use motor manufacturer's recommendations. |
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the main service panel are not recommended. |
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Some motors are supplied with maximum |
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Overcorrection may result, causing potential |
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KVAR recommendations. |
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problems to the capacitors and adjacent connected |
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equipment. In this case individual motor correction |
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3) |
Use motor data supplied by motor manufacturer, |
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or an Automatic Capacitor System would be the best |
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when full load power factor and full load amps are |
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known. First, multiply full load amps times |
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voltage times 1.723 and divide by 1000. This result |
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DETERMINE TOTAL REQUIREMENT |
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is KVA. Next, multiply the KVA times the power |
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In order to determine the overall KVAR requirements, |
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factor. This result is the KW. Next, use Table 3 below to |
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the normal load KW and the original power |
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determine the KVAR required to raise the full |
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factor must be known. This information can usually |
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load Power Factor to the desired level. |
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be obtained from the electric utility bill or from the |
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local power company. To compute the total KVAR |
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4) |
Use Tables 1 & 2 below which list the recommended |
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required, refer to Table 3 below and multiply the value |
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sizes of KVAR units needed for correction of |
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found at the intersection of “Original Power |
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most induction motors to approximately 95% |
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Factor” and “Desired Power Factor” by the normal |
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power factor. These tables show the proper |
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load KW. As an example: To improve the power |
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KVAR for a given horsepower and RPM. |
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factor of a 400 KW load from .77 to .92 : |
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Caution: |
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Certain motor applications are not suitable for |
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connecting the capacitor to the load side of the motor |
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In the above example, 161.2 KVAR would be |
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starter. Applications involving reversing, plugging, |
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required to correct the complete system. If individual |
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or frequent starts; crane or elevator motors, or any |
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motors are being corrected, the KVAR being |
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motor where the load may drive the motor, multispeed |
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connected to individual motors is subtracted from |
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motors, or motors using open transition |
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the overall KVAR required for the entire system. |
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reduced voltage starting, must be corrected on the |
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The balance would then be connected to the |
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distribution panel or main service panel. |
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distribution system. If the total KVAR required was |
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161.2 as noted in the above example, and 100 |
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KVAR had been connected to individual motors, the |
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balance of 61.2 would be reduced to 60 KVAR and |
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connected to the distribution system. As an alternative, |
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a VAR MANAGER 180 KVAR unit could be |
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used on the main service to correct the whole facility |
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